WebHere you can find the meaning of CsBr crystallises in a body centered cubic lattice... more.The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that … WebApr 7, 2024 · CsBr crystallizes in a body-centered cubic lattice of unit cell edge length 436.6 pm. Atomic masses of Cs and Br are 133 amu and 80 amu respectively. The density ( in g/) of CsBr is: ... this is predicted by …
Density Of Unit Cell - Primitive Unit Cell, Volume Of Unit Cell
WebHere you can find the meaning of CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? defined & explained in the simplest way possible. WebDec 20, 2024 · AB crystallizes in a body centered cubic lattice with edge length ‘a’ equal to 387 pm. asked Aug 28, 2024 in Chemistry by Rutvi (39.8k ... 0 votes. 1 answer `NH_(4)Cl` crystallises in a body centred cubic lattice with a unit cell distance of 387 pm. Calculate (a) the distance between the oppositely charged. asked Nov 2, 2024 in Chemistry by ... eyes open 2 teacher\\u0027s book pdf
CsBr crystallises in a body-centred cubic lattice. The unit
WebCsBr crystallises in a body-centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 amu and that of Br = 80 amu and the Avogadro number being 6.02×10 23 mol-1, the density of CsBr is : 1. 42.5 g / c m 3. 2. 0.425 g / c m 3. 3. 8.25 g / c m 3. 4. 4.25 g / c m 3 WebQuestion: CsBr crystallizes in a body centered cubic lattice. The edge length of unit cell is 436.6 pm. (Molar mass of Cs is 132.9 g/mol, Molar mass of Br is 79.9 g/mole, Avogadro's number 6.02x1023 ions/mol), , the density of CsBr is Select one: a. 42.5 g/cm3 O b. 0.425 g/cm3 O c. 8.25 g/cm3 O d. 4.25 g/cm3 WebApr 24, 2024 · The density of CsBr is . Explanation: Number of atom in unit cell = Z = 4. Density of CsBr = ? Edge length of cubic unit cell= a. Atomic mass of Pt(M) = 195.08 g/mol. Formula used : where, = density. Z = number of atom in unit cell. M = Molar mass of compound = Avogadro's number a = edge length of unit cell. We have: M =133 g/mol + … eyes open 1 teacher\u0027s book pdf