Good reducing nature of h3po2 is due to
WebMar 28, 2024 · These reducing agents reduce other molecules. In case of acids if a central atom is present in its maximum oxidation state then it cannot further increase its oxidation state. So, it would not act as a reducing agent. In \[{H_3}P{O_4}\] , phosphorus is present in its maximum oxidation state $( + 5)$. Hence it will not act as a reducing agent. WebGood reducing nature of H 3PO 2 is attributed to the presence of A Two P-OH bonds B One P- H-Bond C One P - OH bond D Two P- H bonds Medium Solution Verified by …
Good reducing nature of h3po2 is due to
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WebFeb 23, 2024 · We know that In Hypo phosphorous acid (H 3 PO 2) has two H atoms are bonded directly to P atom and In Phosphorous acid (H 3 PO 3) has one H atom is bonded directly to P atom which imparts reducing character to the acid, whereas in H 3 PO 4 there is no H atom bonded directly to P atom hence it does not have reducing character.
WebIn H3PO2 two H atoms are bonded directly to P atom which imparts reducing character to the acid WebH3PO2 is good reducing agent due to presenceof two P–H bonds. lood reducing nature of H3PO2 ttributed to the presence of:a)One P -OH bondb)One P-H bondc)Two P-H bondsd)Two P-OH bondsCorrect answer is option 'C'.
WebThe reducing character of the hydrides of Group 15 elements increases from NH 3 to BiH 3 (Bismuthine) because the reducing character depends upon the stability of the hydride.The greater the unstability of anhydride,the greater is the its reducing character.Since,the BiH 3 is the least stable (because the size of central atom is greatest & therefore its tendency … WebGood reducing nature of H 3PO 2 tributed to the presence of: A one P−OH bonds B one P−H bonds C two P−H bonds D two P−OH bonds Hard Solution Verified by Toppr …
WebApr 25, 2024 · It is a well known fact that negative oxidation state hydrogens are highly reducing in nature; hence, the H atoms attached to the phosphorous atom contribute to …
WebStrong reducing behaviour of H3PO2 is due toa)presence of one –OH group and two P–H bondsb)high electron gain enthalpy of phosphorusc)high oxidation state of phosphorusd)presence of two –OH groups and one P–H bondCorrect answer is option 'A'. Can you explain this answer? Share with a friend Answer this doubt Question Description girly girl shirts wholesaleWeb(i) The low oxidation state of phosphorus (ii) Presence of two –OH groups and one P–H bond (iii) Presence of one –OH group and two P–H bonds (iv) High electron gain … girlygirlsshop poshWebMar 6, 2014 · The oxidation state of sulphur is +4 in SO 2 i.e it can lose its two more electron to attain +6 oxidation state and can act as oxidising agent but it can also gain electrons to reach the oxidation state of -2 state observed in it due to this ability of SO 2 to lose and gain electron and it can acts as oxidising as well as reducing agents. funky formations limitedWebFeb 16, 2024 · Strong reducing behavior of H₃PO₂ is due to (c) presence of one — OH group and two P — H bonds Explanation: Hypophosphorous Acid is an oxyacid of phosphor and is a strong reducing agent.; Phosphorous can have a varying oxidation state from -3 to +5 of which Phosphorous oxyacids may have oxidation states from +1 to +5. Lower … funky free ads.comWebMar 17, 2024 · Strong reducing behavior of H3PO2 is due to the presence of one - OH group and two P - H bonds. The reducing properties of oxyacids of phosphorous are due to the presence of P-H bond. It has high tendency to release protons. Thus exhibits reducing nature. Hence, the correct option is C. Mark me BRAINLIEST Advertisement Advertisement girlygirlsshop poshmarkWebGood reducing nature of H3PO2 is attributed to the presence of : JEE Main 2024 (Online) 9th January Evening Slot p-Block Elements Chemistry JEE Main. ExamSIDE. ... Good reducing nature of H 3 PO 2 is attributed to the presence of : A. Two P $$-$$ OH bonds. B. One P $$-$$ H bond. C. Two P $$-$$ H bonds. D. girly girl shopWebStrong reducing behaviour of H3PO2 is due to (i) The low oxidation state of phosphorus (ii) Presence of two –OH groups and one P–H bond (iii) Presence of one –OH group and two P–H bonds (iv) High electron gain enthalpy of phosphorusSolution: Option (iii) is the answer. 11. On heating lead, nitrate forms oxides of nitrogen and lead. girly girl shoes