Web5 mrt. 2024 ยท Click here ๐ to get an answer to your question ๏ธ which terms of the AP: 21,18,15....is -78 WebSo, the sum of the first 20 terms of the AP is 250. Example: How many terms of the AP: 24, 21, 18 ... must be taken so that their sum is 78? Solution: Here, a = 24, d = 21 24 = 3, S n = 78. We need to find n. We know that S n = n/2 [2a + (n 1) d] Therefore, 78 = n/2 [2 24 + (n 1) (-3)] 78 2 = n [48 3n + 3] 156 = 51n 3n 2
[Solved] Which term of the series 3, 8, 13, 18, _______ is 78?
WebQuestion From - NCERT Maths Class 10 Chapter 5 SOLVED EXAMPLES Question โ 13 ARITHMETIC PROGRESSIONS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION โฆ WebHow many terms of the A.P: 24,21,18,.... must be taken so that their sum is 78? Medium Solution Verified by Toppr โS n= 2n[2a+(nโ1)d] โ78= 2n(2a+(nโ1)d) โ78= 2n(2(24)+(n+1)(โ3)) โ156=n(48โ3n+3) โ156=n(51โ3n) โ156=51nโ3n 2 โ3n 2โ51n+156=0 โ3n 2โ12nโ39n+156=0 โ3n(nโ4)โ3q(nโ4)=0 โn=4 or n= 339=13 Solve โฆ how many episodes are in sankarea
[Solved] The 8th term of an AP is 18 more than the second
WebExample 2: Consider the following AP: 24, 21, 18, โฆ How many terms of this AP must be considered so that their sum is 78? Solution: Let the number of terms that give the sum โฆ Web4 jan. 2024 ยท Given : AP = 24,21.. Sn = 78 . To find : n = ? AP = 24, 21 , 18 .. So, First term of AP = (a) = 24, common difference (d) = (21 - 24) = -3. Let n no. of terms to be taken, So that sum = 78. So, sum of n terms of the AP, Sn = n/2 ร [2a + (n-1)d] Substituting the given value in above formula we get, = n/2 ร (2 x 24 + (n-1) ร (-3) โด n/2 ร ... Web29 mrt. 2024 ยท Here, a = 24 d = 21 โ 24 = โ3 Also, given Sum = 78 Sn = 78 We have to find value of n Putting these values in equation Sum = ๐/๐ [๐๐+ (๐โ๐)๐ ] 78 = ๐/2 [2ร24+ (๐โ1) (โ3)] 78 โฆ high v. weekly ad