How many terms of ap 27 24 21
WebAnswer (1 of 2): How many terms of an AP 27, 24, and 21 should be taken so that their sum is zero? Solution: Sn = 0 = (n/2)[54+(n-1)*(-3)] = n[54+3–3n] = n[57–3n] Since n … WebHow many terms of the A.P; 24,21,18,... must be taken such that their sum is 78 Easy Solution Verified by Toppr Formula, S n= 2n[2a+(n−1)d] Given, a=24,d=21−24=−3,S n=78 78= 2n[2(24)+(n−1)(−3)] 156=n[48−3n+3] 3n 2−51n+156=0 n 2−17n+52=0 (n−13)(n−4)=0 ∴n=4,13 Was this answer helpful? 0 0 Similar questions
How many terms of ap 27 24 21
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Web13 okt. 2024 · Step-by-step explanation: The given AP is,27,24,21,.... Here first term= a=27 common difference=d=24-27=-3 Let the nth term of the AP=0 => a+ (n-1)d=0 =>27+ (n-1) (-3)=0 => (n-1)= (-27)/ (-3) => n-1=9 => n=9+1 => n=10 So, the 10th term of the AP is 0. hope it will help you. Advertisement dawin32arpit Answer: 10 please mark as brainlist answer Web7 sep. 2024 · The term of the A.P. which is 0 is 10th. To answer this question, we need to follow the following steps: As we know the nth term of an AP that has a = first term, d = common difference and n = number of terms till the nth term is given by using the formula: Now, according to the question, We have an A.P. 27, 24, 21. where the first term or a = 27.
Web8 feb. 2024 · answered Feb 8, 2024 by Beepin (59.2k points) selected Feb 9, 2024 by KumkumBharti Best answer In the given A.P; a = 24, d = 4, Sn = 72 we have Sn = n/2 {2a + (n – 1)d} 72 = n/2 {2 (24) + (n – 1) (-4)} = 144 = n {48 – 4n + 4} ⇒ 144 = n {52 – 4n} ⇒ 144 = 52n – 4n2 ⇒ 4n2 – 52n + 144 = 0 ⇒ n2 – 13n + 36 = 0 ⇒ (n – 9) (n – 4) = 0 ∴ n = 9, 4 Web25 aug. 2024 · Click here 👆 to get an answer to your question ️ Which term of the AP: 27, 24, 21, is zero? ytbrijesh ytbrijesh 25.08.2024 Math Secondary School answered Which term of the AP: 27, 24, 21, is zero? See ... How Many soaps measuring 8 cm X 4 cm X 2cm can be arranged in this box ? class interval 1-3 3-5 5-7 7-9 frequency 12 22 27 ...
Web14 apr. 2024 · The team fired Hextall, Burke and assistant general manager Chris Pryor on Friday after the Penguins failed to reach the playoffs for the first time in 17 years. The decision to part with the trio ... WebQuestion From - NCERT Maths Class 10 Chapter 5 SOLVED EXAMPLES Question – 13 ARITHMETIC PROGRESSIONS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-How many t...
WebCLASS-10TH CBSE NCERT BOOK ARITHMETIC PROGRESSION EXAMPLE-13How many terms of the AP: 24, 21, 18, . . . must be taken so that their sum is 78?
Web(viii) – 26, – 24, – 22, …. to 36 terms Solution: In an A.P., if the first term = a, common difference = d, and if there are n terms. Then, the sum of n terms is given by (i) Given A.P.is 50, 46, 42 to 10 term. First term (a) = 50 Common difference (d) = 46 – 50 = – 4 n th term (n) = 10 = 5 {100 – 9.4} = 5 {100 – 36} = 5 × 64 ∴ S 10 = 320 grass fed beef prices in californiaWeb11 apr. 2024 · And the common difference (d) of the A.P is. ⇒ d = ( 21 − 24) = ( 18 − 21) = − 3. Now we have to find out the number of terms in the A.P if the sum of an A.P is 78. As … grass fed beef prices 2021Web12 aug. 2024 · Find an answer to your question how many terms of the ap 27 24 21 .....should be taken so that their sum is zero. hahshha hahshha 12.08.2024 Math Primary … grass fed beef ottawa ontarioWeb18 mrt. 2024 · Given A.P. is 27, 24, 21. . . We know that, Sn = n 2 n 2 [2a + (n − 1)d] Here we have, the first term (a) = 27. The sum of n terms (Sn) = 0. Common difference of the … chittara moodo velege song lyricsWebThe given AP is 27, 24, 21, .. First term of the AP = 27. Common difference = 24 − 27 = −3. Let the sum of the first x terms of the AP be 0. Sum of first x terms = x 2 … grass fed beef prices packagesWebConsider the following AP: 24, 21, 18..... How many terms of this AP must be taken so that their sum is 78? [4 MARKS] Solution Formula: 1 Mark Concept: 1 Mark Application: 2 … grass fed beef prices on the hoofWeb30 mrt. 2024 · Transcript. Ex 9.2,4 How many terms of the A.P. 6, 11/2, 5 . are needed to give the sum 25? AP is of the form 6, 11/2, 5 . Here First term = a = 6 Common difference = d = 11/2 ( 6) = 11/2 + 6 = ( 11 + 12 )/2 = 1/2 & Sum of n terms = Sn = 25 We need to find n We know that Sn = n/2 [2a + (n 1)d] Here, Sn = 25 , a = 6 , d =1/2 Putting values 25 = … chittaranjan cancer hospital newtown